Hmmmm... This doesn't feel right.
Yeah. Now that you've mentioned, it feels like someone's putting words in my mouth...
Can anyone explain what in the hay is goin' on?
Well, according to my calculations, we're stuck in an example page. Everything we do and say has been crafted by the author to test out the website features.
Such as different paragraphs in the same dialog.
Or splitting dialogs into two.
That's not creepy at all.
Look, now they made me make a different face!
Ooo, oo! Me too!
Check this out. Now they're gonna make me quote my entire monolog from when we befriended Thorax, to test how long paragraphs look. "You're a celebrity here in the Crystal Empire, and you just risked all of it for a friend! I can't imagine anything more brave than that. [to others] As the Princess of Friendship, I try to set an example for all of Equestria. But today, it was Spike who taught me that a new friend can come from anywhere. I guess everypony still has things to learn about friendship. Even me! And if Spike says Thorax is his friend, then he's my friend too.", to which I'm pretty sure Cadence proceeds with "On behalf of the Crystal Empire, I would like to extend my hoof in friendship, and I'm sure all of my subjects are eager to do the same."
I must say, I feel something else coming. I think I'm about to... $$f(x) = x^2$$
What happened?!
Now the author is making us spit out some mathematical formulas, to ensure they look nice. For example, how inline equations look like $\sum_{i = 1}^n i = n(n+1)/2$ but block equations look like $$\sum_{i = 1}^n i = \frac{n(n+1)}{2}$$ Can you feel it too?
Indeed, darling. I'm feeling positively inclined to recite a 3x3 jacobian matrix! $$ \def\arraystretch{2.2} \begin{bmatrix} \dpartial{f_x}{x} & \dpartial{f_x}{y} & \dpartial{f_x}{z} \\ \dpartial{f_y}{x} & \dpartial{f_y}{y} & \dpartial{f_y}{z} \\ \dpartial{f_z}{x} & \dpartial{f_z}{y} & \dpartial{f_z}{z} \end{bmatrix} $$
We're all speakin' in fancy! $\alpha\beta\gamma\delta\varepsilon\zeta\eta\theta\iota\kappa\lambda\mu\nu\xi\pi\rho\sigma\tau\upsilon\phi\chi\psi\omega$
Okay... that was just the greek alphabet. They didn't even try to come up with a sentence? Sounds lazy to me. $$\text{shush } \textbf{ i'm just } \textit{ testing stuff } \textbf{\textit{ okay?}}$$ Sigh. Sure.
My turn! My turn!! Pick me! Pick me!! Me me mememememe!!!! $$ \begin{alignat}{1} & \dpartial{\rho}{t}+\dpartial{(\rho u_i)}{x_i} = 0 \\ & \dpartial{(\rho u_i)}{t}+\dpartial{(\rho u_i u_j)}{x_j} = -\dpartial{p}{x_i}+\dpartial{\tau_{ij}}{x_j}+\rho f_i \\ & \dpartial{(\rho e)}{t}+(\rho e+p)\dpartial{u_i}{x_i} = \dpartial{(\tau_{ij} u_j)}{x_i}+\rho f_i u_i+\dpartial{(\dot{q}_i)}{x_i}+r \\ & \vec{\nabla}\cdot(\rho\vec{u}) = 0 \\ & \dpartial{(\rho \vec{u})}{t}+\vec{\nabla}\cdot\rho\vec{u}\otimes\vec{u} = -\vec{\nabla p}+\vec{\nabla}\cdot\bar{\bar{\tau}}+\rho\vec{f} \\ & \dpartial{(\rho e)}{t}+\vec{\nabla}\cdot(\rho e+p)\vec{u} = \vec{\nabla}\cdot(\bar{\bar{\tau}} \cdot\vec{u})+\rho\vec{f}\vec{u}+\vec{\nabla}\cdot\vec{\dot{q}}+r \end{alignat} $$
Pinkie!! Did you just recite the entirety of the Navier-Stokes equations??
Hmmmm... It seems so. In fact, I think I know the solution. It's-
We don't have time for thissss. Are we done yet?
This section of the page is still in construction.
Interesting. They also have a "WIP" segment for when they don't have the time to continue or don't feel inspired enough to keep writing.